Write structural function for each of the following :

a)three ethers with formula C4H10O

b)A secondary alcohol with the formula C3H6O

c)Three secondary alkyl halides with the formula C5H11Br

d)A tertiary alkyl halide with the formula C5H11Br

An ether is a R-O-R' where "R" and "R'" are organic groups. You have C4H10 to build the Rs.

Alcohols are R-OH. A secondary alcohol has RR'C-OH where the two R groups are attached to the C.

Alkyl bromides are R-Br. Halides include other halogens (F, Cl, Br, I). Secondary halides (including bromides) have the same structure as secondary alcohols.

Tertiary halides are RR'R"C-OH where all of the R-groups are attached the one C.

Just arrange the Carbons and Hydrogens so that each carbon is attached to four other things and the hydrogen is attached to only one thing.