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View Full Version : Solving Exponentials


slack
Feb 11, 2009, 05:17 PM
Solve the following for x exactly.
9^(x)-16*3^(x)=-60

galactus
Feb 11, 2009, 06:29 PM
Rewrite as:

(3^{x})^{2}-16\cdot 3^{x}+60=0

Now, let u=3^{x} and treat as a quadratic.