The following function declaration guarantees the values in the array argument are not changed.

void function1(int array[ ], int numElements);

Err why don't you have a think about it

Hint: if I try this:

array[0] = 4;

would that change the 1st value of your array?

The following function declaration guarantees the values in the array argument are not changed.

void function1(int array[ ], int numElements);

You should write the function1 by this:

Int array[20];
Void function1(array,int numElements)

If there's array[],you couldn't use '[]' inside the function()

I don't know if you get the point...
Good luck!