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xotica
Dec 16, 2008, 08:50 PM
Suppose you roll 4 dice.

a) What is the probability that you get 4 different numbers?

b) What is the probability that you get '2 pairs' (two of one number and
two of another number?)

c) Now suppose that you continue rolling 4 dice over and over until you get
either get '4 different numbers' or 'two pairs'. What is the probability
that you get 'two pairs' first?

Credendovidis
Dec 17, 2008, 06:02 PM
Dear xotica

Here is a LINK to a website where you can find all the info you need to answer these questions. (http://mathforum.org/library/drmath/sets/select/dm_dice.html)

Success !

:)

galactus
Dec 17, 2008, 07:44 PM
b) What is the probability that you get '2 pairs' (two of one number and
two of another number?)

Count them up. Let's pair them.

1122, 1133,1144,1155,1166,2233,2244,2255,2266,3344,3355, 3366,4455,4466,5566

Each of these can be arranged in 6 ways.

(15)(6)=90

There are 6^{4}=1296 total arrangements.

xotica
Dec 17, 2008, 08:45 PM
Does anyone know c?