2x^2-3x=1

2x^2-3x=1

2x²-3x=1
so 2x²-3x-1=0 ------ let A

let ax²+bx+c=0
hence x=(-b±?(b²-4ac))/2a ------ let B

here from A & B

a=2, b=-3, c=-1

so x=[-(-3)±?((-3)²-4.2.-1)]/2.2

hence x=[3±?(9+8)]/4

x=[3±?17]/4

hence x1=[3+?17]/4 or x2=[3-?17]/4

x1=[3+4.123]/4 or x2=[3-4.123]/4

2x²-3x=1
so 2x²-3x-1=0 ------ let A

let ax²+bx+c=0
hence x=(-b±?(b²-4ac))/2a  ------ let B

here from A & B

a=2, b=-3, c=-1

so x=[-(-3)±?((-3)²-4.2.-1)]/2.2

hence x=[3±?(9+8)]/4

         x=[3±?17]/4

hence x1=[3+?17]/4  or x2=[3-?17]/4

         x1=[3+4.123]/4  or x2=[3-4.123]/4
   
x1=1.78 or x2=-0.28
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