Find the sum of all the integers from 150 to 366.

Use the formula for the sum of the n integers and subtract them.

\sum_{k=1}^{n}k=\frac{n(n+1)}{2} for the integers up to 149

Then do the same for 366

Then subtract the two results.

Find the sum of all the integers from 150 to 366.
I don't understand what your have there
What answer you got let me compare it to my answer

What's your answer? I just gave the formula for the sum of the first n integers.

Well-known if you're studying sequences.

What answer you [did you get,] let me compare it to my answer.

If you post your answer we can help you with it, we can't just give you the answer, then we would be doing your homework.

Find the sum of all the integers from 150 to 366.
My answer is 55836

You're off by 150. Should be 55986.

That is why we sum from 1 to 149 and then 1 to 366 and subtract.

\frac{149(150)}{2}=11175

\frac{366(367)}{2}=67161

67161-11175=55986

See?

Find the sum of all the integers from 150 to 366.
Evaluate the sum of the first 125 terms of the series whose nth term is equal to (2 n - 12).
Could you help me with this one also

The nth term is 2n-12. So, if we look at it, we are summing up the even integers from -10 to 238.

-10-8-6-4-2-0+2+4+6+8+... +238

The nth partial sum is given by S_{n}=\frac{n}{2}(a_{1}+a_{n})

Where n=125 and a_{n}=238; \;\ a_{1}=-10

Find the sum of all the integers from 150 to 366.
That's the answer your got

Find the sum of all the integers from 150 to 366.
I got the answer for the previous one. Thanks a lot man I really appreciate it very much could you help with this one I got this answer 2.3

Find the infinite sum of the sequence
10, −3, 0.9, −0.27, 0.0809999999999999, …