This is another question id highly appreciate you guys help me with

A driver has a reaction time of 0.5s and the maximum deceleration of his car is 6.0m/s2. He is driving at 20 m/s when suddenly he sees an obstacle in the road 35 m in front of him.
a)
Can he stop the car in time to avoid a collision?
b)
How fast was the car going 3 seconds after he saw the obstacle?
c)
The speed limit in the area is 60 km/hr. If he were obeying the speed limit, would the outcome be any different? If so, how?

THANXX

Hello "malb"

I'm not going to provide you the reply : that you have to do yourself ! But I'll try to set you in the right direction !

Delay time = 0.5 sec
Max decel. = 6.0m/s2.
Ini. Speed = 20 m/s (= 72 Km/sec)
Total L = 35 meter.
Before reacting 0.5 x 20 mtr = 10 mtr. Was already driven.
Remains a total of 25 meter to decelerate = distance
(Total time required to stop = 20/6 sec.)

With these data you can now calculate the answer to the questions.

You can find how to calculate that here (LINK) (http://www.csgnetwork.com/stopdistinfo.html)

Make sure to check the Vehicle Stopping Distance Calculator to see if your reply is correct.

Success !

:)

You guys are so helpful
Thank you so much :)
But I don't get how to use the calculator

Please help further please