An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 1.80 s later is -5.00 cm, what is its acceleration?

Use x=x_{0}+v_{0}t+\frac{1}{2}at^{2} and solve for a.

x=-5, \;\ x_{0}=3, \;\ t=1.8, \;\ v_{0}=14