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View Full Version : Solving radical eqautions


akays
May 19, 2008, 03:03 PM
How do you solve radical equations?

mathstinkz1
May 24, 2008, 08:34 AM
I^5 -6i^4-3i^-3i

galactus
May 24, 2008, 11:48 AM
i^5 -6i^4-3i^-3i

There is a pattern to the i powers

i=1\\i^{2}=-1\\i^{3}=-1\\i^{4}=1, then it starts over.

Suppose you wanted i^{1703}.

Just divide 1703 by 4 and look at the remainder. 425 with remainder of 3. Therefore, it is equal to -1. See?

3i^{-3i}=3e^{\frac{3\pi}{2}}