Absolute value??

y= -lx+2l+3

how do I graph it?? Please help?

Plot the points on a graph.
x=3 -> y=-2
x=2 -> y=-1
x=1 -> y=0
x=0 -> y=1
x=-1 -> y=2
x=-2 -> y=3
x=-3 -> y=4

You'll notice that you have a straight line!

Plot the points on a graph.
x=3 -> y=-2
x=2 -> y=-1
x=1 -> y=0
x=0 -> y=1
x=-1 -> y=2
x=-2 -> y=3
x=-3 -> y=4

You'll notice that you have a straight line!
I disagree...

Following the equation y= -lx+2l+3

For x=-3, y= -|-3+2| +3
y=-|-1|+3
y=-1+3
y=2

Absolute values make a V shaped graph.

So essentially what you have is this:
x=3 -> y=-2
x=2 -> y=-1
x=1 -> y=0
x=0 -> y=1
x=-1 -> y=2
x=-2 -> y=3
but then when you get to x=-3 you notice a change:
x=-3 -> y=2
x=-4 -> y=1
x=-5 -> y=0

Here's the graph:

Nice, galactus. What did you use to make that? It's pretty spiffy.

I done that with a FREE graphing download you can get at Graph (http://www.padowan.dk)

Download it. It's absolutely free. It graphs standard, parametric, and polar. As well as finding area, finding tangent lines, etc.

x -1 0 1
Y=3x+5

plot the points and draw a straight line through the ponts.
from the graph,find:-
the values of y when x=2,0.6 and 1.5
the values of x when y=1,0.8 and 2.9