Log in

View Full Version : Linear equations... finding the value of a straight line


McNuggy@LMC
Feb 13, 2006, 02:26 AM
hi there... can you answer this for me please.

or even give a better layman understanding of how to interprete the formula.

the equation is

y-y1=m(x-x1) ------ (1,2) gradient 3


is m the gradient or is x1 the gradient

arrrgh I`m trying to help my little brother here and its hard because the book is not in front of me, that said I`m not the best at algebra or math really. I do have a little bit of memory from school but considering it was 11 years ago its kind of blurry
thanks for any help you can give me

happybisaya
Feb 13, 2006, 02:06 PM
formula: y-y1 = m(x-x1)
point: (1,2)
slope: 3

y-2 = 3(x-1)
y-2 =3x-3
+2 +2
_________
y = 3x-1 ------ Answer; equation of the line

happybisaya
Feb 13, 2006, 02:10 PM
Oh I forgot to answer your other question. 3 is your gradient or slope.

McNuggy@LMC
Feb 19, 2006, 04:39 PM
Thank you very much mr happy... I`m still in the dark but my little brother has figured it out and he also thanks you for your reply. Cheers:) :) :)

happybisaya
Feb 19, 2006, 05:33 PM
thankyou very much mr happy..... i`m still in the dark but my little brother has figured it out and he also thanks you for your reply. cheers:) :) :)

You are welcome.