Pavilion1
Apr 9, 2008, 06:36 AM
I think I have the equation right but I can't get it balanced. The equation is
HNO3+H2O+Cu(II)=Cu(NO3)2+NO+H2O. The original was dilute nitric acid, copper metal dissolves to form aqueous cupric nitrate, nitrogen monoxide gas, and water. Can someone set me in the right direction?
HNO3+H2O+Cu(II)=Cu(NO3)2+NO+H2O. The original was dilute nitric acid, copper metal dissolves to form aqueous cupric nitrate, nitrogen monoxide gas, and water. Can someone set me in the right direction?