galactus
Feb 29, 2008, 07:49 PM
\sqrt{3x+2}. What is (2,00)? Is that supposed to be (2,\infty)
If so, I am sorry, no. You have the infinity part correct. The 2 is not right.
In order to be in the domain, you can not have a negative inside the radical. That results in complex numbers and they are not part of the real domain.
If you solve 3x+2>0, then you can find your domain.