mainepenguin
Feb 2, 2008, 12:14 PM
Hey guys I've been working on this one trig identity for about an hour and I can't seem to make it work it out. Any help will be appreciated
(tan/1+cos) + (sin/1-cos) = cos + sec*csc
galactus
Feb 2, 2008, 12:54 PM
The identity is equal to cot(x)+csc(x)sec(x), not cos(x).
\frac{tan(x)}{1+cos(x)}+\frac{sin(x)}{1-cos(x)}
You can cross multiply, this gives:
\frac{tan(x)-tan(x)cos(x)+sin(x)+cos(x)sin(x)}{sin^{2}(x)}
Now, if you expand and simplify each, you will whittle it down to the right side.
Which is cot(x)+csc(x)sec(x). Having that cos(x) in there may have been the problem.