View Full Version : Half-life equations
 
 adestree
Jan 29, 2008, 02:52 PM
The half-life of 9142Mo is 15.5 minutes. If you start with 3.5 x 1022 atoms of 9142Mo, how many atoms will remain after 31 minutes? 
 
 
The half-life of 31H is 12.26 years. If you start with 2.0 x 1015 atoms of 31H, how many atoms will remain after 36.78 years? 
 
 
The half-life of 6932Ge is 30 hours. If you start with 3.0 X 105 atoms of 6932Ge, how many atoms will remain after 120 hours? 
 
 
The half-life of 146C is 5730 years. If you start with 2.5 X 109 atoms of 146C, how many atoms will remain after 28,650 years? 
 
 
The half-life of 198O is 29.1 seconds. If you start with 1.5 x 1022 atoms of 198O, how many atoms will remain after 4 minutes and 51 seconds?
 Capuchin
Jan 29, 2008, 03:02 PM
Just use the equation that you have probably been given:
 
N(t) = N_0e^{-\lambda t}
 
Where:
 
\lambda = \frac{ln(2)}{t_{1/2}}
 iroc90
Jan 15, 2011, 11:07 PM
number 1 : 
 
n =3.5 ee 22 * e^- (31/15.5)
 
n = 3.5 ee 22 * 2.718281828459^ - ( 31/15.5)
 
n = 3.5 ee 22 * 2.718281828459^-2 
 
n = 3.5 ee22 * 1.3533528323661269189399949497248e-1
 
n = 4.7363491328144* 10^21 atoms left 
 
Number 2: 
 
 
n = 2.0 *10^15* e ^ -  (36.78 / 12.26)
 
n = 2.0 *10^ 15 * 2.718281828459^ - 3
 
n = 2.0 *10^15 * 0.049787068368 
 
n = 9.957413673573e+13 Atoms of H3 atom
 
 
Number 3 : 
 
n = 3.0 *10^5 *e^-(120/30) 
 
n =  3.0* 10 ^5 *  2.718281828459^ -4 
 
n = 3.0 *10^5 * 0.018315638889
 
n =  5494.691666620254 germanium 69  
 
 
Number 4 : 
 
n = 2.5 * 10^9 e^ -( 28650 / 5730 ) 
 
n = 2.5* 10^9 *2.718281828459 ^ -  5
 
n = 2.5 * 10^9 * 0.006737946999
 
n= 1.684486749771 e+7 atoms of carbon 14 
 
Number 5 : 
 
n = 1.5 *10^22 * e - ( 291/29.1) 
 
n = 1.5 * 10^22 * 2.718281828459^ - (10) 
 
n = 1.5 * 10^22 * 4.539992976249 e-5 
 
n = 6.809989464373 e+17 atoms of oxygen 19
 Unknown008
Jan 16, 2011, 12:48 AM
number 1 : 
 
n =3.5 ee 22 * e^- (31/15.5)
 
n = 3.5 ee 22 * 2.718281828459^ - ( 31/15.5)
 
n = 3.5 ee 22 * 2.718281828459^-2 
 
n = 3.5 ee22 * 1.3533528323661269189399949497248e-1
 
n = 4.7363491328144* 10^21 atoms left 
 
WRONG. You didn't use ln(2)
 
The actual answer is 8.75 x 10^21
 
 
Number 2: 
 
 
n = 2.0 *10^15* e ^ -  (36.78 / 12.26)
 
n = 2.0 *10^ 15 * 2.718281828459^ - 3
 
n = 2.0 *10^15 * 0.049787068368 
 
n = 9.957413673573e+13 Atoms of H3 atom
 
Wrong again... 
 
Ans: 2.5 x 10^14
 
 
 
Number 3 : 
 
n = 3.0 *10^5 *e^-(120/30) 
 
n =  3.0* 10 ^5 *  2.718281828459^ -4 
 
n = 3.0 *10^5 * 0.018315638889
 
n =  5494.691666620254 germanium 69  
 
Wrong... 
 
 
Ans: 1.875 x 10^4 = 1.88 x 10^4
 
 
 
Number 4 : 
 
n = 2.5 * 10^9 e^ -( 28650 / 5730 ) 
 
n = 2.5* 10^9 *2.718281828459 ^ -  5
 
n = 2.5 * 10^9 * 0.006737946999
 
n= 1.684486749771 e+7 atoms of carbon 14 
 
Wrong... 
 
Ans: 7.8125 x 10^ 7 = 7.81 x 10^7
 
 
Number 5 : 
 
n = 1.5 *10^22 * e - ( 291/29.1) 
 
n = 1.5 * 10^22 * 2.718281828459^ - (10) 
 
n = 1.5 * 10^22 * 4.539992976249 e-5 
 
n = 6.809989464373 e+17 atoms of oxygen 19
 
Wrong... 
 
Ans: 4.935 x 10^19 = 4.94 x 10^19
 
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