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Henshaw1
Jan 21, 2008, 07:06 PM
4th root of (3x^4 x y^2)

jiten55
Jan 21, 2008, 08:15 PM
4th root of (3x^4 x y^2):

Remember: 4th root x^a = x^(a/4)

nth root of x^m = x^(m/n)

5th root of (ab) = (fifth root of a)(fifth root of b)

We are discouraged from solving homework questions, so I am going to solve a problem similar to yours, so that you can solve your particular problem:

6th root of (6x^6 times y^3)

= (6x^6)^1/6 (y^3)^1/6

= 6^(1/6) (x^6)^1/6 (y^3)^1/6

= 6^(1/6) x y^(3/6)

= 6^(1/6) x y^1/2

josehduran7
Sep 3, 2008, 10:10 PM
the radical of y^(4/7)

arturdo968
Sep 7, 2008, 06:52 PM
how would you solve this?
(-1/64) ^ -1/3

Niederta
Nov 17, 2008, 05:07 PM
Square Root of 50