I am in algebra IIa right now and,
I had a quiz on this stuff today, and I think I might if did it wrong. I couldn't ask me teacher yet, until I have the quiz graded.

Find the missing terms ____8_____ _____44
The lines are the missing #'s

Find the Sn when given a1=4, n=12, and d=16

write 3+4+5+6+7 in sigma notation

please!
Thank you!

can you please explain your answeres too, and like show work please
thanks

-10, 8, 26, 44 (A.P. with d = 18)

Another interesting possibility: 2, 8, 20, 44,.

(multiply each term by 2 and add 4, to get the next term; OR the difference gets double each time)

For the second part, A1= 4, Find : An = A1 + (n-1)d

After that

Sn = n(A1 + An)/2

-10, 8, 26, 44 (A.P. with d = 18)

Another interesting possibility: 2, 8, 20, 44,.

(multiply each term by 2 and add 4, to get the next term; OR the difference gets double each time)

For the second part, A1= 4, Find : An = A1 + (n-1)d

After that

Sn = n(A1 + An)/2


Find the missing terms ____8_____ _____44
The lines are the missing #'s

This is what i meant: Find the missing terms _?___8__?___ __?___44
so 3 terms are missing not just 2. a # before 8 and 2 #s after the 8.



what do you mean for the second part? Do you mean that's the second step for the 10, 8, 26, 44? Or is that the answere for the "Find the Sn when given a1=4, n=12, and d=16?"

Sn = n(A1 + An)/2? What is that shouldn't that be in the sigma notation for? You know that big E(sum) with the #s around it?

1. 12, 8, 20, 32, 44

Because: 44 is 5th term and 8 is second term

44 - 8 = 3d

d = 12

2. by second part I mean Sn.

A1 is first term, An is nth term. Sn is the sum of n terms.

An = 4 + 16 (12 -1) = 4 + 176 = 180

Sn = 12 (4 + 180)/2

3. For Sigma, I don't know how to type it:

Sigma x (x from 3 to 7)

Yeah thank you you for the help! I just got my quiz back today and those are the questions I got wrong lol, but now I get it!

THanks again!
Abdul