View Full Version : Solve for z 3x(y+1)=9+z where y=4, x=2
resa35
Nov 16, 2007, 08:54 AM
Solve for z 3x(y+1)=9+z where y=4, x=2
Can you help me solve step by step
asterisk_man
Nov 16, 2007, 09:59 AM
substitute y=4 and x=2, simplify and solve. Why don't you show us your work and let us know where you're having problems.
plynia
Nov 18, 2007, 12:04 PM
Solve for z 3x(y+1)=9+z where y=4, x=2
Can you help me solve step by step
OK
3x(y+1)=9+z
3(2)(4+1)=9+z
6(4+1)=9+z
6(5)=9+z
30=9+z
30-9=9+z-9
21=z