This is a trigonometry problem. How do you find the inverse cosecant of 2, the square root of 2, and -2. The answer must be in radians. I don't want anyone to do my homework for me, I just want to know how to do it lol.

I assume you have a calculator with only sine, cosine, and tangent?

In that case, type in sin^{-1}(1/2)=csc^{-1}(2), \;\ sin^{-1}(\frac{1}{\sqrt{2}})=csc^{-1}(\sqrt{2}) and so forth.

Set your calculator to radians first. If it's in degrees, multiply by \frac{\pi}{180}