On a sales trip, Gail drives the 600 miles to Richmond at a certain speed. The return trip is made at a speed that is 10 mph slower. Total time for the round trip was 22 hours. How fast did Gail travel on each part of the trip?

This doesn't sound correct. You say Gail drives 600 miles at a CERTAIN SPEED, and then the return trip is made at a SPEED THAT IS 10MPH SLOWER.

How can you determine how fast gail was going if you didn't know the speed she was going in the first place.

Am I missing something here ?

I guess you didn't learn anything when you asked the square route of 22 to the near est thousand. Hey, and you got a good answer!! Did you follow it through ?

This is just classic d=rt. We can use d/r=t, since we are given the distance and time.


\frac{600}{r}+\frac{600}{r-10}=22

Solve for r. You will get two solutions. Only one will be viable.