what is the limit as x-->0 when tan^2x / x

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I will give you a website on math.
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I am not trying to get someone to do my hw!! I have worked hard on this problem and I cannot figure it out. I was just looking for some help. Even if someone could me the first step! Not the answer!! Shyrgrneyzs

Try rewrting as :

\lim_{x\to\0}\left(\frac{sin^{2}(x)}{x}\cdot\frac{ 1}{cos^{2}(x)}\right)

That mean sinx/x--> 1 because of properties of limits. And that leaves sinx(1/cos^2x)

Another thing you could do is use L'Hopital.

Find the derivative of tan^{2}x

That is 2sec^{2}(x)tan(x)

The derivative of x is 1, so you have:

2\lim_{x\to\0}sec^{2}(x)tan(x)

Is that easier?


BTW, \lim_{x\to\0}\frac{sin^{2}x}{x}=0, not 1.

I didn't say that. I said sinx/x is 1.

My teacher helped me solve the problem and gave the answer 0.
Thanks for the help.

I know you didn't say that. I was pointing it out from my previous post. Yes, the answer is 0.