How do I solve

3(4+3)to the second power-1??

Gahh.
I hate algebraa!

Give you a hint. Do the bit in the brackets first!!

3(3+4)to power of-1= 3(7)to power of-1= 3x7to power of -1=21 to power of -1= 21x-1=
-21
See how I did that?

I don't see much algebra. Just basic arithmetic.

so would that be (21^-1)^-1? I hate computer math!

3(3+4)to power of-1= 3(7)to power of-1= 3x7to power of -1=21 to power of -1= 21x-1=
-21
See how I did that?
Um, no.

so would that be (21^-1)^-1 ?? i hate computer math!
Again, no.



3(4+3)to the second power-1???
This could be either x^2 - 1
or ax^2 - 1.

I think the later, you try it from here.

3(4+3)to the second power-1
3(4+3)^2 -1
3(7)^2-1
3*49 - 1
147 - 1
146

The other possibility would be:
(3*(4+3))^2 - 1
(3*7)^2 -1
21^2 -1
441 - 1
440

Any questions?