OK so I totally forgot how to do logs here's a problem I have
log (base 3) x squared = 2log (base 3)4 - 4log (base 3)5

Some rules to remember about logs:

n \times log_a b = log_a b^n



log(a/b) = log (a) - log (b)




log (a*b) = log (a) + log (b)


You can use these rules to simplify your problem. For example:


4 \times log_3 5\ =\ log_3 5^2


Can you continue from there?

Solv this logarithems 2log16(base2)+4log8(base2)-3log64(base2)

Solv the logarithems:-log8(base6)+2lod3(base6)+log12(base6)-log24(base6)

You can use the rules above given by ebaines to solve these.