Hi there

Could you please help me with this question?

(log10 with 10 being the base of the log)

If log10(y)=-log10(2x), then y in terms of x is:

log(y)=-log(2x)

log(y)=log(\frac{1}{2x})

Since the bases are both 10, we just have y=\frac{1}{2x}