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nike23
Jul 12, 2007, 08:19 AM
sumone help me simplify these? The "^" means to the power of the number that follows it

√54x^3y^5

2√12x^4y^5

0.5√8x^4y^3

3√75x^3y^5

4√x^3yz^6

Capuchin
Jul 12, 2007, 08:28 AM
Here's a trick for you.

Let's take a made up example:

6 \sqrt{4x^2y}

Now, a square root is the same as raising to the power of 0.5 so:

6 \sqrt{4x^2y} = 6(4x^2y)^{\frac{1}{2}}

Now we can use power rules:

6(4x^2y)^{\frac{1}{2}} = 6(4^{\frac{1}{2}}(x^2)^{\frac{1}{2}}y^{\frac{1}{2} }) = 6(\sqrt{4}x^{2*\frac{1}{2}}y^{\frac{1}{2}}) = 6(2x \sqrt{y}) = 12x \sqrt{y}

Simple eh?

Now you have a go at yours.

nike23
Jul 12, 2007, 08:40 AM
Lol, its not as easy as you say it is. Can u help me do at least one or 2 of my selected problems?

s_cianci
Jul 15, 2007, 07:51 PM
Break down each coefficient inside of each radical in the usual way. For example, 54 = 9 * 6 , 12 = 4 * 3 , etc. As for the variables, divide each exponent by 2. The quotient becomes the power of the rational part that comes out of the radical and the remainder (which will be 0 or 1 and the 0 case will be redundant) becomes the power of the irrational part which stays inside the radical.

ShannonMathWiz
Apr 15, 2008, 06:00 PM
Chigga Chigga Wha