7x^-8*6x^3

Okay,

Do you have a question?

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Okay,

Do you have a question?

how can I do this problem x+1 over x+3 =2

\frac {x+1}{x+3}=2

Remember your axioms.

You can add anything to both sides of an equation and you will still have an "equation" (sides are equal). Equals added to equals are equal.
You can subtract anything to both sides of an equation and you will still have an "equation" (sides are equal). Equals subtracted from equals are equal.
Same thing with multiplication and division.

The first thing you do is try to get everything in the numerator. To do that, multiply both sides of the equation by something that will get rid of the denominator on the left side. Hint: You'll end up with this equation after you simplify:

(x+1)=(2x + 6).

After that, you will have multiples of x plus a constant on the left and a (possibly different) multiple of x plus another constant on the right. You can get all of the multiples of x on the same side by either adding or subtracting some multiple of x to both sides. Also, you can add or subtract something to both sides to effectively get all of the constants on the side opposite of the side where the x's are. You'll end up with something like this:

ax =b where a and b are numbers.

If you then divide both sides by the coefficient of x, a, you will have solved the problem.

7x^-8*6x^3

7x^{-8} \, \times \, 6x^3

or

6x^3 \, \times \, 7x^{-8}

The next question is, "What do you want to do with this?" Is this an equation to be solved like this?

6x^3 \, \times \, 7x^{-8} = 0