1. Write the slope-intercept form of the line that passes through the point (-2,-5) and is parallel to the line y=-6x+1.

2. Find all real zeros of the function: g(x)=2x(cubed)-x(squared)-10x+5

3. Write the polynomial as a product of linear factors. x(cubed)-2x(squared)-9x+18

4. Multiply (x+1)(2x-1)(x+3)

5. (-7x"squared"+3) + (4x"squared" + 2x -1)

6. A certain gas will escape from a storage tank according to the formula e=140(the square root of p), where e represents the amount escaping per minute in gallons and p represents the pressure in pounds per square inch. What is the pressure on the gas when about 280 gallons per minute are escaping?

2. Find all real zeros of the function: g(x)=2x(cubed)-x(squared)-10x+5
g(x)=2x^3-x^2-10x+5=x^2*(2x-1) -10*(2x-1)=(2x-1)*(x^2-10)

-> g(x) == 0 <=> 2x-1 == 0 OR x^2-10 == 0 <==> x == 1/2 OR x = +- square root( 10 )


3. Write the polynomial as a product of linear factors. x(cubed)-2x(squared)-9x+18
This is the same thing as above, except you don't have to find the real zeros. Just use the previous example, and it will be easy to figure it out.


4. Multiply (x+1)(2x-1)(x+3)
You're kidding, right?


5. (-7x"squared"+3) + (4x"squared" + 2x -1)
What are you supposed to do with this?


6. A certain gas will escape from a storage tank according to the formula e=140(the square root of p), where e represents the amount escaping per minute in gallons and p represents the pressure in pounds per square inch. what is the pressure on the gas when about 280 gallons per minute are escaping?
e = escaping amount of gas per minute (in gallons) = 280

e = 140*square root( p ) -> square root( p ) = e / 140 -> p = ( e / 140 )^2

Do the rest on your own.