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    babi_gurl's Avatar
    babi_gurl Posts: 30, Reputation: 2
    Junior Member
     
    #1

    Feb 25, 2007, 01:22 AM
    Constant acceleration
    Hey I was wondering if anyone can help me on this problem below :)

    The velocity of a particle moving in a straight ine with uniform acceleration increases from 10m/s to 20m/s in 30m. When and where was the velocity 15m/s


    Thx:D
    agneau's Avatar
    agneau Posts: 3, Reputation: 1
    New Member
     
    #2

    Feb 25, 2007, 01:54 AM
    v^2 = u^2 + 2as
    (v = init vel, u = fin vel, a - accel, s = displacement)

    solving for a gives: a = (v^2 - u^2)/2s

    since the particle accelerated from 10m/s to 20m/s in 30m...

    a = (20^2 - 10^2)/2*30
    a = 5 m/s^2

    back to v^2 = u^2 + 2as

    solving for s:
    s = (v^2 - u^2)/2a

    this time the final velocity is 15 and we want s

    s = (15^2 - 10^2)/2*5
    = 11.5m

    and as v = u + at

    t= (v - u)/a
    = (15-10)/5 = 1s

    sothe velocity was 15m/s after 1s and 11.5m

    hope I'm right and hope it makes sense... it's been a while since I've had to do these and it was fun dredging those equations of motion back from my memory.

    a
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
    Uber Member
     
    #3

    Feb 25, 2007, 03:58 AM
    Hi agneau, this looks right to me

    However I recommend when the question is clearly homework, it's often more suitable to hint, rather than to give the full answer, this helps the OP to learn, rather than just copy down the answer.

    If the OP has obviously tried to have a go at the problem, then we generally help a little more. The effort we give them depends on the amount of effort they give us.

    Welcome to the site :)

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