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    bre07's Avatar
    bre07 Posts: 1, Reputation: 1
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    #1

    Aug 22, 2010, 01:01 PM
    How do I write the standard form equation of the circle -6y= -x^2-16x-y^2-72
    Please show the work so I can understand
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Aug 22, 2010, 01:51 PM

    Bring everything to the left side, but leave the -72



    Group x's and y's, then 'complete the square' by adding the square of half the coefficient of x and y.



    Factor each group:



    That's it. It has center (-8,3) and radius=1
    stedan01's Avatar
    stedan01 Posts: 1, Reputation: 1
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    #3

    Aug 26, 2010, 02:40 PM

    50-2x10+4
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #4

    Aug 28, 2010, 08:35 AM
    Quote Originally Posted by stedan01 View Post
    50-2x10+4
    Straighten up.:rolleyes:
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