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Full Member
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Mar 7, 2009, 06:00 PM
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Challenging Math Quest|on!
Edited. If you are curious as to what this post said, please scroll down to the link below.
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Jobs & Parenting Expert
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Mar 7, 2009, 06:09 PM
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1 out of 3
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Full Member
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Mar 7, 2009, 06:19 PM
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Anybody else? And if you could explain why, I would love to hear it.
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Full Member
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Mar 7, 2009, 06:58 PM
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Woops, I meant to say your answer is incorrect, and that the correct answer is C, but I was going to give you props anyway. :)
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Uber Member
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Mar 7, 2009, 07:00 PM
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It doesn't matter if they reveal a "goat door" or not, and doesn't matter if the member switches.
There are always three doors, and always only one car.
The only possible arrangements are
1 2 3
G g c
G c g
C g g
That's it... now look down vertically... if you choose ANY door, you will always have a 1 in 3 chance.
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Uber Member
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Mar 7, 2009, 07:02 PM
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Actually, I was wrong and I get it.
Ill explain...
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Uber Member
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Mar 7, 2009, 07:06 PM
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assuming
1 2 3
g g c
g c g
c g g
if I choose door 1, scenario 1 ( g g c)... they'll show me door 2 and I, by your rules, must switch to 3 = car
if I choose door 1, scenario 2 (g c g)... they'll show me door 3 and I must switch to 2 = car
if I choose door 1, scenario 3 (c g g)... they'll show me door 2 or 3, and ill switch to a goat door = no car.
so choosing door one, with a goat door revealed, and a mandated switch (what I ignored at first) will get me a car in 2 or 3 tries.
same goes for any other door chosen.
my mistake was ignoring the mandated switch.
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Ultra Member
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Mar 7, 2009, 07:14 PM
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Full Member
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Mar 7, 2009, 07:36 PM
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Woot! Ty kp2171! I appreciate your efforts greatly!
galactus is correct. Thanks for the link!
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