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Yeah, I was just given the formula you specified...
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I did do the same thing, but the answer is not consistent with the solution given.. For a) the solution given is 0.9961...
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Hi.. This is a question I found in a text that I am unable to solve.. Help would be appreciated..
"Because not all airline passengers show up for their reservation, an airline sells 125 tickets for...
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You should start by getting the expression in the form of 't= (.. )' once u have reduced the expression , it is just normal diffrentiation wrt x. Try doing it.. u may need to use logarithms to get...
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I think thr is some error in your ans.. for x=1/2, the only value for y is -13/12..
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Proceed according to the following steps:
1. Find a relation between radius(r) and height(h) of the cone.
2. Substitute for 'r' in terms of 'h'in the volume equation of the cone.
3. Find...
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Thanks a lot.. one more question, if I need to find the normal to a given unit vector, how do I go about it..
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If I have 2 vectors A and B in 3D,how do I find the normal component and parallel component of one on another??
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The notation given by jerry is exactly right.. The answer given is 5/3... I don't know how to arrive at it..
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how do u find the value of 'sigma' from n=-infinity to infinity for (1/2)^(2 mod n)..
sorry wasn't able to put it in the right format..
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This wasn't an assignment.. I just came across it in a book, so I thought of working it out.. thats it..
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the factor of 9 can be accounted for if u consider that Q is distributed among 3 spheres equally.. this implies that value of 'q'is Q^2/9 rite..
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it can further be reduced to -1/sin(x) =-csc(x)
{2 sinAcosA = sin 2A}
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d^2(z)/ dt^2 = 0
How do we integrate this twice?
Please give me the steps of working too..
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It is a spot deviod of photoreceptors(rods and cones).It is this point where the optic nerves exit the eye and moves towards the brain.
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Thank u.. I got the solutuion..
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Thank u.. I got the solutuion..
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Three identical small spheres of mass 'm' are suspended by threads of negligible masses and length'l' from a common point.A charge'q' is equally b/w the spheres and they come to equilibrium at the...
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