Why caan't i find the accelaration i tried and tried and i still couldn't find it

niqua3 · #1 May 31, 2008, 08:28 AM

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 1.80 s later is -5.00 cm, what is its acceleration?

ebaines · Jun 2, 2008, 07:59 AM

Use the formula:

$<br /> x_f = x_i + v_i t + \frac 1 2 a t^2<br />$

Here $x_i$ is +3 cm, $x_f$ is -5 cm, $v_i$ is +14 cm/s, and $t$ is 1.8s. Solve for $a$ .



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