one more question ...plzz help

rabbia · #1 Sep 23, 2003, 05:58 PM

A stone is thrown from a bridge with a initial vertical velocity of magnitude 4.0m/s. Determine the stone's velocity after 2.2s if the direction of the initial velocity is
a) upward
b)down ward
neglect air resistance
>?
how can i do this question

Bilal Yaqub Bandeesha · Jan 20, 2008, 08:06 PM

use vf=vi+gt for downward

jiten55 · Jan 21, 2008, 01:21 AM

The formula is: v = u + at

Where: v = final velocity, u = initial velocity, a = acceleration

If thrown upward, acceleration = -g

If thrown downward, acceleration = g

justindq · May 16, 2008, 08:01 AM

use the formular v = u + at, where a is represented by g, being the force of gravity. a = -g if stone is thrown upwards and a = g when stone is thrown downwars. Hence for (a) formular is v = u - gt
and for (b) v = u + gt.

kesavan · May 16, 2008, 09:19 AM

These equations are vector equations. You can use any direction, but put components in the same directions



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