Trig identities

jbenevidesfh6 · #1 May 20, 2007, 12:57 PM

How can I solve..
cotx + cosx sinx/ tanx +conx sinx/ cotx = csc2?

ebaines · May 21, 2007, 10:31 AM

Do you mean:

$<br /> cot(x) + \frac {cos(x) sin(x)}{tan(x)}+ \frac{cos(x) sin(x)}{cot(x)} = csc(2)<br />$

If so, then try rewriting using sin() and cos() in place of the the tan() and cot() functons, and much of it collapses to a simpler looking equation. You'll end up having to determine the arc tan of a number.



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