# Probability Distribution

Determine the value of c so that each of the following functions can serve as a probability distribution of the discrete random variable X:

(a) f(x) = c(x^2 + 4) for x=0,1,2,3;
(b) f(x) = c(2,x)(3,3-x) for x=0,1,2

 waqassiddiqui Posts: 10, Reputation: 1 New Member #2 Mar 20, 2008, 08:36 AM
Solution:

a)

x 0 1 2 3

f(x) 4 5 8 13

F(0) = f(0) = 4
F(1) = f(0) + f(1) = 4 + 5 = 9
F(2) = f(0) + f(1) + f(2) = 4 + 5 + 8 = 17
F(3) = f(0) + f(1) + f(2) + f(3) = 4 + 5 + 8 + 13 = 30

how can I calculate c

and in the book answer is 1/30.

b)

=c(2+3,x+3-x)
=c(5,3)
=10

can anybuddy explain
 eng_Hamdan Posts: 2, Reputation: 10 Junior Member #3 Mar 14, 2011, 03:30 AM
âˆ‘f(x) =1

make summation of the functions f(0),f(1),f(2)...

then you can find c
 eng_Hamdan Posts: 2, Reputation: 10 Junior Member #4 Mar 14, 2011, 03:31 AM
Comment on eng_Hamdan's post
Quote:
 Originally Posted by eng_Hamdan âˆ‘f(x) =1 make summation of the functions f(0),f(1),f(2)... then you can find c
sum f(x) =1

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