| 95% confidence level I will rephrase your problem slightly.
If we take n samples from a population that has the normal distribution with mean MU and standard deviation SIGMA, and calculate the sample mean XBAR from our sample, then what is the value for n so that the probability is 95% that XBAR will be close to MU?
(XBAR - MU)/(SIGMA/SQUAREROOT(n)) = 1.96
SQUAREROOT(n) = 1.96SIGMA/.95
n = (1.96SIGMA/.95)^2 |