linear equations....finding the value of a straight line

McNuggy@LMC · #1 Feb 13, 2006, 12:26 AM

hi there....can you answer this for me please.

or even give a better layman understanding of how to interprete the formula.

the equation is

y-y1=m(x-x1) ------ (1,2) gradient 3

is m the gradient or is x1 the gradient

arrrgh i`m trying to help my little brother here and its hard cuz the book is not in front of me, that said i`m not the best at algebra or math really. i do have a little bit of memory from school but considering it was 11 years ago its kinda blurry
thanks for any help you can give me

happybisaya · Feb 13, 2006, 12:06 PM

formula: y-y1 = m(x-x1)
point: (1,2)
slope: 3

y-2 = 3(x-1)
y-2 =3x-3
+2 +2
_________
y = 3x-1 ------ Answer; equation of the line

happybisaya · Feb 13, 2006, 12:10 PM

Oh I forgot to answer your other question. 3 is your gradient or slope.

McNuggy@LMC · Feb 19, 2006, 02:39 PM

thankyou very much mr happy..... i`m still in the dark but my little brother has figured it out and he also thanks you for your reply. cheers

happybisaya · Feb 19, 2006, 03:33 PM

Quote:

Originally Posted by McNuggy@LMC

thankyou very much mr happy..... i`m still in the dark but my little brother has figured it out and he also thanks you for your reply. cheers

you are welcome.



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