integration, either im loosing it or ive been working too long

albear · #1 Jun 17, 2007, 07:27 AM

i need to integrate 1000(2t+1)^-2

i thought it would go [(1000(2t+1)^-1)/-1 ] * t

albear · Jun 17, 2007, 08:15 AM

sorry how do you apply dt=du/2 to get 500(integral)(1/u^2)du

albear · Jun 17, 2007, 10:16 AM

hello

ebaines · Jun 18, 2007, 12:39 PM

You are trying to solve:

$<br /> <br /> \int \frac 1 {(2t+1)^2} dt<br /> <br />$

correct?

So replacing 2t+1 by u, and dt by du/2 gives you the form that Gallactus suggests. Now you should be able to integrate that form, and then the last step is to substitute 2t+1 for u to get the final answer.



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