# Algebra

Hello Friends

The question is.

(x+3)/(x^2+3x+2) = 3/(x+3) + 4/(x^2 +4x+3)

Thank you friends

Ilan

 Capuchin Posts: 5,319, Reputation: 3601 Uber Member #2 Jun 2, 2007, 08:27 AM
That isn't a question.
ilanshan (Jun 20, 2007 07:40 AM): this solved by others on the web   Source:
 galactus Posts: 2,272, Reputation: 1436 Ultra Member #3 Jun 2, 2007, 09:30 AM
I assume you're solving for x. First, factorize the denominators.
 Capuchin Posts: 5,319, Reputation: 3601 Uber Member #4 Jun 20, 2007, 09:39 AM
Ilanshan, I believe you missed my point, it wasn't a question. You just gave an equation, You didn't tell me what to do with it.
 Capuchin Posts: 5,319, Reputation: 3601 Uber Member #5 Jun 21, 2007, 05:19 AM
Quote:
 Originally Posted by galactus I assume you're solving for x. First, factorize the denominators.
Can't we solve it for $3\sqrt{5}+2$?
 galactus Posts: 2,272, Reputation: 1436 Ultra Member #6 Jun 21, 2007, 05:31 AM
Factor first:

$\frac{x+3}{x^{2}+3x+2}=\frac{3}{x+3}+\frac{4}{x^{2 }+4x+3}$

$\frac{x+3}{(x+1)(x+2)}=\frac{3}{x+3}+\frac{4}{(x+1 )(x+3)}$

The LCD is (x+1)(x+2)(x+3)

Now continue.

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