algebra

ilanshan · #1 Jun 2, 2007, 05:09 AM

Hello Friends

The question is.

(x+3)/(x^2+3x+2) = 3/(x+3) + 4/(x^2 +4x+3)

Thank you friends

Ilan

Capuchin · Jun 21, 2007, 04:19 AM

Quote:

Originally Posted by galactus

I assume you're solving for x. First, factorize the denominators.

Can't we solve it for $3\sqrt{5}+2$ ?

galactus · Jun 21, 2007, 04:31 AM

Factor first:

$\frac{x+3}{x^{2}+3x+2}=\frac{3}{x+3}+\frac{4}{x^{2 }+4x+3}$

$\frac{x+3}{(x+1)(x+2)}=\frac{3}{x+3}+\frac{4}{(x+1 )(x+3)}$

The LCD is (x+1)(x+2)(x+3)

Now continue.



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