# Why caan't i find the accelaration i tried and tried and i still couldn't find it

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 1.80 s later is -5.00 cm, what is its acceleration?

 galactus Posts: 2,272, Reputation: 1436 Ultra Member #2 May 31, 2008, 01:26 PM
Use $x=x_{0}+v_{0}t+\frac{1}{2}at^{2}$ and solve for a.

$x=-5, \;\ x_{0}=3, \;\ t=1.8, \;\ v_{0}=14$

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