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Trigonometry quadratic equation
Can you please help me on this, I have just seen that somebody else has asked this question previously but I don't understand how you manage to get two lengths.
Trigonometric Question:- In triangle ABC, the angle A is 42 degrees, the side AB is 16cm and the side BC is 14cm. Find the two possible values of the side AC. How do you get two lengths? |
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One way to solve this is to use the law of cosines, which states:
Here you can substitute 16 for length A, 14 for length C and 42 degrees for angle C, and solve for length B. Because it's a quadratic equation, you'll get two values for length B. See the attached figure and you'll see how that works - the third side of the triangle can be either BC or BC'. |
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