| Calling the heighth of the tree x, the distance to the first measurement y, the first angle a=36.7, and the second angle b=22.2, we have cot a=y/x, so y=x cot a. Also cot b = (y+50)/x = (x cot a + 50)/x = cot a + 50/x, so 50/x = cot b - cot a and so x =
50/(cot b-cot a).
Calling the heigth of the tree x, the distance to the first measurement y, the first angle a=36.7, and the second angle b=22.2, we have cot a=y/x, so y=x cot a. Also cot b = (y+50)/x = (x cot a + 50)/x = cot a + 50/x, so 50/x = cot b - cot a and so x =
50/(cot b-cot a). |