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    lou390's Avatar
    lou390 Posts: 2, Reputation: 1
    New Member
    		  
    #1

    Apr 16, 2004, 06:13 AM
    Trig identities
    How do you prove that (1 - cos2x)/sin2x = tanx?
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
    Junior Member
    		  
    #2

    Mar 2, 2005, 12:53 PM
    Trig identities
    You need to know some identities for sin2x and cos2x:

    sin2x = 2sinxcosx
    cos2x = 1 - 2((sinx)^2); The "^" means raise to the power; "^2" means "raise to the power 2" or "square".


    (1 - cos2x)/sin2x

    = (1 - [ 1 - 2((sinx)^2) ] ) / (2sinxcosx)

    = 2((sinx)^2) / (2sinxcosx)

    = 2sinxsinx / 2sinxcosx

    = sinx / cosx

    = tan x.
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