Solve Radical Equation

tiff1078 · #1 Nov 18, 2007, 02:18 PM

Can someone please help me to solve this equation?

It is 5(square root of y)=y

onfire4God · Nov 18, 2007, 07:52 PM

the answer is simple really.5(the square root of y)=y is because y is to the 0 power and anything times the 0 power equals the # you were multiplying or in your case a letter and the square root of y is the same thing as saying the square root of 1 it equals 1 or in ur case y....... so y divided by y is y times y to the o power =y!!!

asterisk_man · Nov 19, 2007, 10:39 AM

two answers. zero is obviously one of them since y=0 makes both sides 0.

$ 5\sqrt {y}=y \\ 5 {y^{\frac 1 2}}=y \\ 5=\frac y {y^{\frac 1 2}} \\ 5=y^1 {y^{-\frac 1 2}} \\ 5=y^{1-\frac 1 2} \\ 5=y^{\frac 1 2} \\ 5^2=y \\ 25=y $

check

$ 5\sqrt {25}=25 \\ 5*5=25 $



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