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shegun4u · Nov 4, 2009, 05:53 AM

E=mgh+1/2mv(squared) for h

Perito · Nov 4, 2009, 06:06 AM

Subtract 1/2 mv^2 from both sides. Can you figure it out now?

shegun4u · Nov 4, 2009, 06:36 AM

Originally Posted by Perito

Subtract 1/2 mv^2 from both sides. Can you figure it out now?

no. can you write it out?
Thanks

Nhatkiem · Nov 4, 2009, 11:52 AM

Originally Posted by shegun4u

no. can you write it out?
thanks

If you subtract $\frac{mv^2}{2}$ from both sides, you then have

$E-\frac{mv^2}{2}=mgh$

You only need to isolate h now, there is a leading coefficient of "mg" on h. Divide both sides by this coefficient to isolate h.