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    XM8's Avatar
    XM8 Posts: 213, Reputation: 14
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    #1

    Mar 30, 2009, 12:15 PM
    Calculations (cos)
    Hi,

    I'm having a spot of trouble.

    I'm trying to do an exercise (cus I have a maths test tomorrow) and I can't figure this out.

    A = cos (PI/3) - cos(2 PI/3) - cos (4 PI/3) + cos (5 PI/3) = 2

    Why would that equal two? And what am I supposed to be subtracting and adding here? Value such as cos (pi/3) : 1/2 ?

    Please help thanks

    -Xm8
    cdedmundson's Avatar
    cdedmundson Posts: 14, Reputation: 1
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    #2

    Mar 30, 2009, 12:35 PM

    you have the right idea. Cosine is a periodic function so it fluctuates between 1 and -1. it has a period of 2pi, meaning it completes one cycle over a domain of 2pi. So at x=o cos(x)=1, and x=pi cos(x)=-1, and x=pi/3 cos(x)=1/2, just add the four values and they add up to 2
    (1/2)-(-1/2)-(-1/2)+(1/2)=2
    XM8's Avatar
    XM8 Posts: 213, Reputation: 14
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    #3

    Mar 30, 2009, 01:06 PM

    Hey cdEdmundson,

    Thank you for your answer. I understand perfectly what you're saying it's just that I have a small problem and it would be great if you could help me with this.

    Ok I know that the cosine of 2pi/3 is -1/2 as you mentioned above, and that it measures 120 degrees.

    I use a trick my teacher gave me to find the location of any value on the unit circle.

    Let's say he were to give me 97pi/3. What I would do is
    96pi/3 + pi/3 = 32pi + pi/3 and I know that I would have to place the original value, 97pi/3 on the location of pi/3.

    However, how would I decompose, or simplify 2pi/3 or 4pi/3 or even 3pi/3 ?

    Thanks a lot,

    -Xm8
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #4

    Mar 30, 2009, 01:23 PM
    Quote Originally Posted by XM8 View Post
    I know that the cosine of 2pi/3 is -1/2 as you mentioned above, and that it measures 120 degrees.

    I use a trick my teacher gave me to find the location of any value on the unit circle.

    Let's say he were to give me 97pi/3. What I would do is
    96pi/3 + pi/3 = 32pi + pi/3 and I know that I would have to place the original value, 97pi/3 on the location of pi/3.

    However, how would I decompose, or simplify 2pi/3 or 4pi/3 or even 3pi/3 ?
    I subtract 2pi from every value, and repeat until I obtain a number less than 2pi. I then realize that pi radians is 180 degrees. 2pi/3 is simply



    4pi/3 =

    3pi/3 =
    XM8's Avatar
    XM8 Posts: 213, Reputation: 14
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    #5

    Mar 30, 2009, 01:33 PM
    Thanks Edmundson,

    I know how to do that with small values it's just that if I get a big number I can't do the mulitply by 2pi thing because a) I won't have the time to figure it out b) I won't have a calculator and c) The result will be too big

    That's why I try to figure out that rule my teacher gave me because there's always some kind of trick to it.. Hmm... I just don't get it.

    Do you know of any other tricks?

    Thanks,

    -Xm8

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