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Quadratic speed distance time
Asked Oct 2, 2008, 01:12 PM
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3 Answers A woman begins jogging at 3pm, running due north at a 6 minute/mile pace. Later she reverses direction and runs due south at a 7 minute/mile pace. If she returns to her starting point at 3:45, find the total number of miles run. I usually make a chart for Speed, Distance, Time problems such as these. S D T A 6min/mile x x/6min/mile t=d/s B 7min/mile x x/7min/mile Let x be the distance travelled by the woman. I figure X is = to both distance A and B since she runs the same distance there and back. The speeds are given and to find time I divide distance by speed. Here's what I get for an equation: 6x+7x=45 I've tried it several ways so far and I just can't seem to get the right equation. Where am I going wrong!? |
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| This problem is worded wacky. Be careful of units. It is in minutes per mile instead of miles per minute. D=rt. If it takes 6 minutes to run a mile, that is 10 mph. If it takes 7 minutes to run a mile on the way back, then that is about 8.57 mph. 45 minutes is 3/4 hours. 6t=d on the way up. The distances are the same up and back. So, the distance back is 7(3/4-t) | ||||
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| Erison valdez answer Minutes=mt start running at 3:00pm north North=n 3:06=1mln South=s 3:12=2mln Miles=ml 3:18=3mln 3:24=4mln reverse to begin south 3:31=1mls 3:38=2mls 3:45=3mls Total miles ran in 45 minutes= 4mln+3mls=7ml in 45 minutes | ||||
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