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Can you please tell how would would solve this quadratic question:-
The sides of a right-angled triangle are X, (x+2) and (2x-2). The hypotenuse is length (2x-2). Find the actual dimensions of the triangle.
and the Trigonometric Question:-
In triangle ABC, the angle A is 42 degrees, the side AB is 16cm and the side BC is 14cm. Find the two possible values of the side AC. How do you get two lengths?
I understand the second one I figured it out its 2.88cm and 20.9cm, and for the first I still don't understand, can you please just show me how to to it?
what do you get when you multiply it out? I don't give out answers, I try to help you understand the material. Work it out step by step and show me what you get. if you have a specific question, ask away.
To be honest, you've been pretty much just asking for the answer. Forum rules state that I am not to just give you the answer, but to help you work out the answer. If you had just simply worked it out, this would have been painless, but your lazy self simply didn't want to. best of luck with other things in life.
I will go ahead and show you how to do the first one. It is just a matter of solving the resulting quadratic. If I show you, then perhaps it'll help you on further problems?. OK?
I assume you know the Pythagorean theorem.
Your sides are
Now, sit it up:
Now, expand out using foil or whatever and you get:
Can you solve this now?. Use the quad formula or factoring.
Factor out a -2x and you should readily see the two solutions. Only one will be viable and that'll be your solution.