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Home > Education > Homework Help > Math & Sciences   »   Quadratic Equations and Trigonometry

 
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Old May 12, 2008, 10:44 AM
jojo24794
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Quadratic Equations and Trigonometry

Can you please tell how would would solve this quadratic question:-

The sides of a right-angled triangle are X, (x+2) and (2x-2). The hypotenuse is length (2x-2). Find the actual dimensions of the triangle.

and the Trigonometric Question:-
In triangle ABC, the angle A is 42 degrees, the side AB is 16cm and the side BC is 14cm. Find the two possible values of the side AC. How do you get two lengths?


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Old May 13, 2008, 08:49 AM   #11  
galactus
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Quote:
and the Trigonometric Question:-
In triangle ABC, the angle A is 42 degrees, the side AB is 16cm and the side BC is 14cm. Find the two possible values of the side AC. How do you get two lengths?


We can use the law of sines to find angle B and go from there.







Now, since we have C we can easily find angle B by just subtracting the two known angles from 180.



Now, use the law of cosines to find length AC. Can you do that OK?.

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Old May 13, 2008, 09:17 AM   #12  
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Thank you so much your a genius!
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Old May 13, 2008, 10:29 AM   #13  
galactus
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That would be "you're a genius". But thank you.
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Old May 15, 2008, 09:44 AM   #14  
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just out of curiosity, after looking at the above question can i just ask
for this question:
In triangle ABC, the angle A is 42 degrees, the side AB is 16cm and the side BC is 14cm. Find the two possible values of the side AC. How do you get two lengths?
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