Ask Experts Questions for FREE Help !
Ask
    DiMathluv's Avatar
    DiMathluv Posts: 1, Reputation: 1
    New Member
     
    #1

    May 6, 2008, 03:16 PM
    Parabola, using the focus and directrix to determine the equation
    I am having difficulty determining the equation for a parabola when the focus is given, and the directrix is given.

    For example, Focus at (-2, 2) and directrix y= -2. I believe I use the distance formula, however, the distance formula states you need to points X1, Y1, and X2, Y2. I am not given an additional point!

    Help!

    DiMathluv:eek:
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member
     
    #2

    May 6, 2008, 05:20 PM
    No distance formula needed.

    The directrix is at y = -2 and the focus at F(-2,2). That means the vertex is in between.

    It is at V(-2,0).

    Now, we can use

    Where

    With h being the x-coordinate of the vertex and k the y-coordinate. It is h=-2 and k=0 and p=2

    p is the distance between the focus and the vertex.



    Now, express in format:

    Attached Images
     
    erica3's Avatar
    erica3 Posts: 1, Reputation: 1
    New Member
     
    #3

    Oct 15, 2010, 08:07 AM
    The directrix is at y = -4 and the focus at F(0,4). That means the vertex is in between.

Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search


Check out some similar questions!

Find vertex, axis, focus, p, directrix of conic equation [ 8 Answers ]

-4(y+2) = (x-3)^2 I need help finding the vertex, axis, p, focus, and directrix. I'm so blanked out.I cannot remember anything.

Finding an equation being given the foci and the directrix [ 1 Answers ]

foci (4,-1), directrix x=2

Geometry-parabola [ 3 Answers ]

I don't understand the parabola definition and what is the algebraic equation? thank you:)


View more questions Search